POJ 3096 Surprising Strings-白红宇

POJ 3096 Surprising Strings

阅读量：6245 次

发布时间：2019-06-22

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Surprising Strings

Time Limit: 1000MS		Memory Limit: 65536K
Total Submissions: 5081		Accepted: 3336

Description

The D-pairs of a string of letters are the ordered pairs of letters that are distance D from each other. A string is D-unique if all of its D-pairs are different. A string is surprising if it is D-unique for every possible distance D.

Consider the string ZGBG. Its 0-pairs are ZG, GB, and BG. Since these three pairs are all different, ZGBG is 0-unique. Similarly, the 1-pairs of ZGBG are ZB and GG, and since these two pairs are different, ZGBG is 1-unique. Finally, the only 2-pair of ZGBG is ZG, so ZGBG is 2-unique. Thus ZGBG is surprising. (Note that the fact that ZG is both a 0-pair and a 2-pair of ZGBG is irrelevant, because 0 and 2 are different distances.)

Acknowledgement: This problem is inspired by the "Puzzling Adventures" column in the December 2003 issue of Scientific American.

Input

The input consists of one or more nonempty strings of at most 79 uppercase letters, each string on a line by itself, followed by a line containing only an asterisk that signals the end of the input.

Output

For each string of letters, output whether or not it is surprising using the exact output format shown below.

Sample Input

ZGBGXEEAABAABAAABBBCBABCC*

Sample Output

ZGBG is surprising.X is surprising.EE is surprising.AAB is surprising.AABA is surprising.AABB is NOT surprising.BCBABCC is NOT surprising.

Source

刚开始没看懂题意！！！！！！！！

题意如下：

定义D-pairs表示取字符串s中相距为D的两个字母所构成的字母对，该字母对中两个字母的位置顺序与他们在主串s中的位置顺序一致

定义D-unique表示，若从字符串s中取出所有相距为D的字母对D-pairs，且这些D-pairs都是独一无二的，那么成字符串s是一个D-unique串

D的取值范围为0~s.len()-2

假如字符串s对于所有的D都有D-unique成立，则字符串s是令人惊讶的 = =

#include
      
       #include
       
        #include
        
         #include
         #include
          
           using namespace std;char str[110];int main(){    //freopen("input.txt","r",stdin);    map
           
             mp; while(~scanf("%s",str) && str[0]!='*'){ int flag=1; int len=strlen(str); //printf("str=%s\n",str); string tmp; int blank=1; for(int i=0;i

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